In the given circuit,with steady current,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a steady state,the capacitor acts as an open circuit,so no current flows through the middle branch.The current $I$ flows through the outer loop

Vedclass · Accepted Answer

$2V/3$

Vedclass · Answer

(D) In a steady state,the capacitor acts as an open circuit,so no current flows through the middle branch.The current $I$ flows through the outer loop containing the $V$ and $2V$ batteries and the $R$ and $2R$ resistors.Applying Kirchhoff's voltage law to the outer loop:$2V - V = I(R + 2R)$$V = I(3R)$$I = \frac{V}{3R}$The potential difference across the capacitor $C$ is equal to the potential difference between the two nodes to which it is connected.Let the left node be $A$ and the right node be $B$. The potential difference $V_{AB}$ across the capacitor branch is:$V_{AB} = V - I 	imes R$ (or $V_{AB} = 2V - I 	imes 2R$)$V_{AB} = V - (\frac{V}{3R}) 	imes R = V - \frac{V}{3} = \frac{2V}{3}$Thus,the potential drop across the capacitor is $\frac{2V}{3}$.

In the given circuit,with steady current,the potential drop across the capacitor must be

Similar Questions

If $f(0)=0, f(1)=1, f(2)=2$ and $f(x)=f(x-2)+f(x-3)$ for $x=3, 4, 5, \ldots$,then $f(9)$ is equal to

$A$ radioactive material decays by simultaneous emission of two particles with respective half-lives $1620 \, years$ and $810 \, years$. The time, in years, after which one-fourth of the material remains is

Which kingdom includes unicellular or multicellular eukaryotic organisms?

The ratio of specific heats of a gas is $\gamma$. The change in internal energy of one mole of the gas,when the volume changes from $V$ to $2 V$ at constant pressure $p$ is

$X$ and $Y$ are two metals. When burnt in air,$X$ forms only oxide while $Y$ forms oxide and nitride. The metals $X$ and $Y$ may be

Vedclass Test Series

Exam Paper Generator

Online Exam Module