In the given circuit,the current flowing thro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given,the current through the $20 \ \Omega$ resistor is $i_1 = 0.3 \ A$. The total current measured by the ammeter is $I = i_1 + i_2 + i_3 = 0.9 \

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) Given,the current through the $20 \ \Omega$ resistor is $i_1 = 0.3 \ A$. The total current measured by the ammeter is $I = i_1 + i_2 + i_3 = 0.9 \ A$.Since the resistors are connected in parallel,the potential difference $V_{AB}$ across them is the same.$V_{AB} = i_1 	imes 20 \ \Omega = 0.3 \ A 	imes 20 \ \Omega = 6 \ V$.Now,calculate the current $i_2$ through the $15 \ \Omega$ resistor:$i_2 = \frac{V_{AB}}{15 \ \Omega} = \frac{6 \ V}{15 \ \Omega} = 0.4 \ A$.Using the total current equation:$i_1 + i_2 + i_3 = 0.9 \ A$$0.3 \ A + 0.4 \ A + i_3 = 0.9 \ A$$0.7 \ A + i_3 = 0.9 \ A$$i_3 = 0.2 \ A$.Finally,calculate $R_1$ using the potential difference $V_{AB}$ and current $i_3$:$R_1 = \frac{V_{AB}}{i_3} = \frac{6 \ V}{0.2 \ A} = 30 \ \Omega$.

In the given circuit,the current flowing through the resistance $20 \ \Omega$ is $0.3 \ A$,while the ammeter reads $0.9 \ A$. The value of $R_1$ is . . . . . . $\Omega$.

Similar Questions

Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage,the ratio of heat produced in the same time for parallel to series will be:

Three voltmeters $A$,$B$ and $C$ having resistances $R$,$1.5 R$ and $3 R$ respectively are used in a circuit as shown. When a potential difference is applied between $X$ and $Y$,the readings of the voltmeters are $V_{1}$,$V_{2}$,and $V_{3}$ respectively. Then

Two bulbs are connected in parallel. Bulb $A$ is brighter than bulb $B$. If $R_A$ and $R_B$ are their resistances respectively,then:

For what value of $R$ will the net resistance of the circuit be $18 \, \Omega$?

Two resistances are joined in parallel whose resultant is $6/8 \, \Omega$. One of the resistance wires is broken and the effective resistance becomes $2 \, \Omega$. Then the resistance in ohm of the wire that got broken was:

Vedclass Test Series

Exam Paper Generator

Online Exam Module