In the given circuit, calculate $(i)$ total resistance of the circuit, and $(ii)$ current shown by the ammeter.
In the given circuit, calculate $(i)$ total resistance of the circuit, and $(ii)$ current shown by the ammeter.
$(i)$ Since $R _{1}$ and $R _{2}$ are in series, their resultant resistance,
$R _{ S }= R _{1}+ R _{2}=3+2=5 \Omega$
Further, $R _{ S }$ and $R _{3}$ are in parallel, their resultant resistance is given by
$R_{P}=\frac{R_{S} R_{3}}{R_{S}+R_{3}}=\frac{5 \times 5}{5+5}=2.5 \Omega$
$(ii)$ Also, $\quad I=\frac{V}{R}=\frac{2.5}{2.5}=1 A$
Similar Questions
$(a)$ For the circuit shown in the diagram, calculate
$(i)$ value of current through the $30\, \Omega$ resistor.
$(ii)$ total resistance of the circuit.
$(b)$ Give two advantages of connecting electrical devices in parallel with battery.
$(a)$ For the circuit shown in the diagram, calculate
$(i)$ value of current through the $30\, \Omega$ resistor.
$(ii)$ total resistance of the circuit.
$(b)$ Give two advantages of connecting electrical devices in parallel with battery.
A wire of resistance $5 \,ohm$ is bent in the form of a closed circle. What is the resistance between two points at the ends of any diameter of the circle?
A wire of resistance $5 \,ohm$ is bent in the form of a closed circle. What is the resistance between two points at the ends of any diameter of the circle?
When do we say that the resistors are connected in series ?
When do we say that the resistors are connected in series ?
An electric iron consumes energy at a rate of $840\, W$ when heating is at the maximum rate and $360\, W$ when the heating is-at the minimum. The voltage is $220\, V$. What are the current and the resistance in each case ?
An electric iron consumes energy at a rate of $840\, W$ when heating is at the maximum rate and $360\, W$ when the heating is-at the minimum. The voltage is $220\, V$. What are the current and the resistance in each case ?
The unit of measurement of charge is coulomb.
The unit of measurement of charge is coulomb.