In the Freundlich isotherm frac{x}{m}=k p^{fr | vedclass

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(B) For the Freundlich adsorption isotherm equation:$\frac{x}{m} = k p^{\frac{1}{n}}$Taking the logarithm on both sides:$\log \frac{x}{m} = \log (k p^

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$\log k$

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(B) For the Freundlich adsorption isotherm equation:$\frac{x}{m} = k p^{\frac{1}{n}}$Taking the logarithm on both sides:$\log \frac{x}{m} = \log (k p^{\frac{1}{n}})$$\log \frac{x}{m} = \log k + \frac{1}{n} \log p$Comparing this with the linear equation $y = mx + c$,where $y = \log \frac{x}{m}$,$x = \log p$,slope $m = \frac{1}{n}$,and intercept $c = \log k$.Thus,the intercept of the plot is $\log k$.

In the Freundlich isotherm $\frac{x}{m}=k p^{\frac{1}{n}}$ plot of $\log \frac{x}{m}$ vs $\log p$,the intercept is (where,$x$,$m$,$p$ and $k$ are mass of the gas,mass of adsorbent,pressure and constant which depend on the nature of the adsorbent,respectively)

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