In the following sequence of reactions,the final product $C$ is:
$CH_{3}Br$ $\xrightarrow{KCN} A$ $\xrightarrow{H_{2}O} B$ $\xrightarrow{LiAlH_{4}} C$

  • A
    Acetone
  • B
    Methane
  • C
    Acetaldehyde
  • D
    Ethyl Alcohol

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