In the following sequence of reactions,the fi | vedclass

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(D) Step $1$: $CH_3-C \equiv CH + NaNH_2 \rightarrow CH_3-C \equiv C^- Na^+ (A) + NH_3$. Step $2$: The nucleophile $(A)$ reacts with $4$-bromopentan-$

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$CH_3-CH_2-CH_2-CH_2-CH_2-CO-CH_3$

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(D) Step $1$: $CH_3-C \equiv CH + NaNH_2 \rightarrow CH_3-C \equiv C^- Na^+ (A) + NH_3$. Step $2$: The nucleophile $(A)$ reacts with $4$-bromopentan-$2$-ol to form $B$ $(CH_3-C \equiv C-CH_2-CH_2-CH(OH)-CH_3)$. Step $3$: Hydrogenation with $H_2/Pd-C$ reduces the alkyne to an alkane,yielding $C$ $(CH_3-CH_2-CH_2-CH_2-CH_2-CH(OH)-CH_3)$. Step $4$: Oxidation with $CrO_3$ converts the secondary alcohol into a ketone,yielding $D$ $(CH_3-CH_2-CH_2-CH_2-CH_2-CO-CH_3)$.

In the following sequence of reactions,the final product $D$ is:

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