In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{S}OCl_2 + H_2O \longrightarrow H_2SO_3 + HCl$
$\underline{S}OCl_2 + H_2O \longrightarrow H_2SO_3 + HCl$
- AIf the product is an oxy acid with an $-ic$ suffix.
- BIf the product is an oxy acid with an $-ous$ suffix.
- CIf the products are two oxy acids,one with an $-ic$ suffix and the other with an $-ous$ suffix.
- DIf the product is not an oxy acid,neither with an $-ic$ suffix nor with an $-ous$ suffix.
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ List-$II$ $A$. Coke $I$. Carbon atoms are $sp^3$ hybridised $B$. Diamond $II$. Used as a dry lubricant $C$. Fullerene $III$. Used as a reducing agent $D$. Graphite $IV$. Cage like molecules
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $A$. Coke | $I$. Carbon atoms are $sp^3$ hybridised |
| $B$. Diamond | $II$. Used as a dry lubricant |
| $C$. Fullerene | $III$. Used as a reducing agent |
| $D$. Graphite | $IV$. Cage like molecules |
Choose the correct answer from the options given below:
MediumNEET 2023
View SolutionWhich of the following elements shows a stable $+2$ oxidation state?
Medium
View SolutionConsider the following reaction:
$R_2SiCl_2 + H_2O \to (1) \xrightarrow{\text{polymerisation}} (2)$
Compound $(2)$ in the above reaction is:
$R_2SiCl_2 + H_2O \to (1) \xrightarrow{\text{polymerisation}} (2)$
Compound $(2)$ in the above reaction is:
Medium
View SolutionAssertion $(A)$: The maximum covalency of $Si$ and $Ge$ is $6$ but that of carbon is $4$.
Reason $(R)$: Due to the presence of $d$-orbitals in $Si$ and $Ge$,both these elements can undergo $sp^3d^2$ hybridisation and covalency of $6$ is possible. Carbon has no $d$-orbitals in it and hence its covalency is $4$.
The correct answer is:
Reason $(R)$: Due to the presence of $d$-orbitals in $Si$ and $Ge$,both these elements can undergo $sp^3d^2$ hybridisation and covalency of $6$ is possible. Carbon has no $d$-orbitals in it and hence its covalency is $4$.
The correct answer is:
Which of the following statements is correct?
Medium
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