In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{S}O_2 + H_2O \longrightarrow H_2SO_3$
$\underline{S}O_2 + H_2O \longrightarrow H_2SO_3$
- AIf the product is an oxyacid with an $-ic$ suffix.
- BIf the product is an oxyacid with an $-ous$ suffix.
- CIf the products are two oxyacids,one with an $-ic$ suffix and the other with an $-ous$ suffix.
- DIf the product is not an oxyacid,neither with an $-ic$ suffix nor with an $-ous$ suffix.
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Match the following:
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A$. Carbon black | $I$. Electrodes in batteries |
| $B$. Graphite | $II$. Extraction of metals |
| $C$. Diamond | $III$. Abrasive |
| $D$. Activated charcoal | $IV$. Filler in automobile tyres |
| | $V$. Air conditioning system |
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A$. Carbon black | $I$. Electrodes in batteries |
| $B$. Graphite | $II$. Extraction of metals |
| $C$. Diamond | $III$. Abrasive |
| $D$. Activated charcoal | $IV$. Filler in automobile tyres |
| | $V$. Air conditioning system |
Which of the following is the most stable?
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View SolutionWhich one of the following is used to convert sunlight into electricity in photovoltaic material?
$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to.........
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View SolutionThe three elements $X$,$Y$ and $Z$ with electronic configurations shown below all form hydrides:
Element Electronic configuration $X$ $1s^2, 2s^2, 2p^2$ $Y$ $1s^2, 2s^2, 2p^6, 3s^1$ $Z$ $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2, 4p^5$
Which set of properties match correctly with properties of the hydrides of these elements?
| Element | Electronic configuration |
| $X$ | $1s^2, 2s^2, 2p^2$ |
| $Y$ | $1s^2, 2s^2, 2p^6, 3s^1$ |
| $Z$ | $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2, 4p^5$ |
Which set of properties match correctly with properties of the hydrides of these elements?
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