In the following reaction sequence,X and Y,re | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction sequence involves the conversion of an alkene to an epoxide followed by the reduction of the epoxide to an alcohol.$1$. The conversio

Vedclass · Accepted Answer

$C_6H_5COOH$; $LiAlH_4$

Vedclass · Answer

(B) The reaction sequence involves the conversion of an alkene to an epoxide followed by the reduction of the epoxide to an alcohol.$1$. The conversion of an alkene to an epoxide (epoxidation) requires a peroxyacid. $C_6H_5COOH$ (perbenzoic acid) is a standard reagent for this transformation.$2$. The reduction of an epoxide to an alcohol requires a strong reducing agent like $LiAlH_4$,which attacks the less hindered carbon of the epoxide ring to yield the corresponding alcohol.Therefore,$X = C_6H_5COOH$ and $Y = LiAlH_4$.

In the following reaction sequence,$X$ and $Y$,respectively,are:
$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$

Similar Questions

$CH_3-CH_2-CH_2-Br + NaOH \xrightarrow{C_2H_5OH} \text{Product } A$. Consider the above reactions,identify product $B$ and product $C$.

In the reaction sequence:
$\text{Ethanol}$ $\xrightarrow{PCl_5} X$ $\xrightarrow{\text{alc. } KOH} Y$ $\xrightarrow[H_2O, \Delta]{H_2SO_4, \text{room temp.}} Z$
The product $Z$ is:

The product $(A)$ is:

An alcohol on oxidation is found to give $CH_3COOH$ and $CH_3CH_2COOH$. The structure of the alcohol is

Assertion : Alcohols are dehydrated to hydrocarbons in the presence of acidic zeolites.
Reason : Zeolites are porous catalysts.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the following reaction sequence,$X$ and $Y$,respectively,are:$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$