In the following reaction,C_6H_5CONH_2 xright | vedclass

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(C) The given reaction is the Hoffmann bromamide degradation reaction.In this reaction,an amide $(RCONH_2)$ reacts with bromine $(Br_2)$ in the presen

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Aniline

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(C) The given reaction is the Hoffmann bromamide degradation reaction.In this reaction,an amide $(RCONH_2)$ reacts with bromine $(Br_2)$ in the presence of a strong base like potassium hydroxide $(KOH)$ to form a primary amine $(RNH_2)$ with one carbon atom less than the starting amide.The reaction for benzamide is:$C_6H_5CONH_2 + Br_2 + 4KOH \rightarrow C_6H_5NH_2 + K_2CO_3 + 2KBr + 2H_2O$Here,benzamide $(C_6H_5CONH_2)$ is converted into aniline $(C_6H_5NH_2)$.Therefore,the major product is aniline.

In the following reaction,
$C_6H_5CONH_2 \xrightarrow{Br_2/KOH} \text{Major Product}$
the major product is

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In the following reaction,$C_6H_5CONH_2 \xrightarrow{Br_2/KOH} \text{Major Product}$the major product is