In the following reaction $C_6H_5CH_2Br \xrightarrow{1. Mg, \text{ ether } \atop 2. H_3O^{+}} X$,the product $X$ is
- A$C_6H_5CH_2OCH_2C_6H_5$
- B$C_6H_5CH_2OH$
- C$C_6H_5CH_3$
- D$C_6H_5CH_2CH_2C_6H_5$
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