In the following indicator diagram,the net am | vedclass

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(B) In a $P-V$ diagram,the work done in a cyclic process is equal to the area enclosed by the cycle.$1$. For a clockwise cycle,the work done is positi

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Negative

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(B) In a $P-V$ diagram,the work done in a cyclic process is equal to the area enclosed by the cycle.$1$. For a clockwise cycle,the work done is positive.$2$. For an anticlockwise cycle,the work done is negative.In the given diagram,cycle $1$ is clockwise,so the work done $W_1 > 0$. Cycle $2$ is anticlockwise,so the work done $W_2 The net work done is $W_{net} = W_1 + W_2$.Since the area of cycle $2$ is larger than the area of cycle $1$ $(|W_2| > |W_1|)$,the negative work dominates the positive work.Therefore,the net work done is negative.

In the following indicator diagram,the net amount of work done will be

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