In the following figure,two parallel metallic | vedclass

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(D) The electric field $E$ is directed from higher potential to lower potential. Here,the potential of the left plate is $-200\, V$ and the right plat

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Accelerated leftward

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(D) The electric field $E$ is directed from higher potential to lower potential. Here,the potential of the left plate is $-200\, V$ and the right plate is $-400\, V$. Since $-200\, V > -400\, V$,the electric field is directed from the left plate to the right plate (rightward).An electron,being a negatively charged particle,experiences an electrostatic force $F = qE$ in the direction opposite to the electric field.Since the electric field is directed rightward,the force on the electron will be directed leftward.According to Newton's second law,$F = ma$,the electron will experience an acceleration in the direction of the force.Therefore,the electron will accelerate leftward.

In the following figure,two parallel metallic plates are maintained at different potentials. If an electron is released midway between the plates,it will move:

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