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(D) For the object of mass $m$ to be at rest,the net force acting on it must be zero.Three forces act on the object: the horizontal force $F$,the grav

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$\sqrt{F^2 + m^2g^2}$

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(D) For the object of mass $m$ to be at rest,the net force acting on it must be zero.Three forces act on the object: the horizontal force $F$,the gravitational force $mg$ acting downwards,and the tension $T$ in the string.According to the condition of equilibrium,the vector sum of these forces must be zero:$\vec{F} + m\vec{g} + \vec{T} = 0$$\vec{T} = -(\vec{F} + m\vec{g})$The magnitude of the tension $T$ is given by the vector sum of the horizontal force $F$ and the vertical weight $mg$,which act at an angle of $90^{\circ}$ to each other:$T = \sqrt{F^2 + (mg)^2}$$T = \sqrt{F^2 + m^2g^2}$Thus,the force exerted by the string on the block is $\sqrt{F^2 + m^2g^2}$.

In the following figure,the object of mass $m$ is held at rest by a horizontal force $F$ as shown. The force exerted by the string on the block is

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