In the following figure, the magnet is moved | vedclass

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(B) According to Faraday's law of electromagnetic induction, the induced emf $e$ is proportional to the rate of change of magnetic flux, which depends

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$2e$

Vedclass · Answer

(B) According to Faraday's law of electromagnetic induction, the induced emf $e$ is proportional to the rate of change of magnetic flux, which depends on the relative velocity between the magnet and the coil.In the first case, the magnet moves towards the stationary coil with speed $v$. The relative velocity is $v_{rel} = v$. The induced emf is $e = k \cdot v$, where $k$ is a constant.In the second case, the magnet and the coil move away from each other, each with speed $v$. The relative velocity between them is $v'_{rel} = v - (-v) = 2v$.Since the induced emf is directly proportional to the relative velocity, the new induced emf $e'$ will be:$e' = k \cdot (2v) = 2(k \cdot v) = 2e$.Therefore, the induced emf in the coil will be $2e$.

In the following figure, the magnet is moved towards the coil with a speed $v$ and the induced emf is $e$. If the magnet and the coil recede away from one another, each moving with a speed $v$, the induced emf in the coil will be

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