In the following compounds,the order of basic | vedclass

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(D) $(I)$ Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital and there is no resonance.$(II)$ In pyridine,the $N$ lone pai

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$I > III > II > IV$

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(D) $(I)$ Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital and there is no resonance.$(II)$ In pyridine,the $N$ lone pair is in an $sp^2$ hybrid orbital. The $sp^2$ hybrid is smaller than the $sp^3$ hybrid,so there is a stronger attraction to the nucleus,making it less basic than $I$.$(III)$ In morpholine,the $N$ lone pair is in an $sp^3$ hybrid orbital. However,the electron-withdrawing effect of the $O$ atom in the ring makes the lone pair less available for donation compared to piperidine.$(IV)$ Pyrrole is a very weak base. The $N$ lone pair is involved in the aromatic sextet. Protonation would destroy the aromaticity,which is an energetically unfavourable process.Therefore,the correct order of basicity is $I > III > II > IV$.

In the following compounds,the order of basicity is:
$I$: Piperidine
$II$: Pyridine
$III$: Morpholine
$IV$: Pyrrole

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In the following compounds,the order of basicity is:$I$: Piperidine$II$: Pyridine$III$: Morpholine$IV$: Pyrrole