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(D) Given: $E_0 = 200 \, V$,$R = 20 \, \Omega$,$L = 0.1 \, H$,$C = 10.6 \, F$.$1$. At frequency $f = 0$ ($DC$ source):The inductive reactance is $X_L

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Zero,zero

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(D) Given: $E_0 = 200 \, V$,$R = 20 \, \Omega$,$L = 0.1 \, H$,$C = 10.6 \, F$.$1$. At frequency $f = 0$ ($DC$ source):The inductive reactance is $X_L = 2 \pi f L = 0 \, \Omega$.The capacitive reactance is $X_C = \frac{1}{2 \pi f C} = \infty$.Since the components are in series,the total impedance $Z = \sqrt{R^2 + (X_L - X_C)^2} = \infty$.Therefore,the current $I = \frac{E_0}{Z} = 0 \, A$.$2$. At frequency $f = \infty$:The inductive reactance is $X_L = 2 \pi f L = \infty$.The capacitive reactance is $X_C = \frac{1}{2 \pi f C} = 0 \, \Omega$.Since the components are in series,the total impedance $Z = \sqrt{R^2 + (X_L - X_C)^2} = \infty$.Therefore,the current $I = \frac{E_0}{Z} = 0 \, A$.Thus,in both cases,the current is zero.

In the following circuit,the emf of the source is $E_0 = 200 \, V$,$R = 20 \, \Omega$,$L = 0.1 \, H$,and $C = 10.6 \, F$. If the frequency is variable,then the current at frequency $f = 0$ and $f = \infty$ is:

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