In the following circuit,the correct relation | vedclass

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(C) The circuit consists of two diodes $D_1$ and $D_2$ connected to inputs $A$ and $B$,followed by an $npn$ transistor.If both inputs $A$ and $B$ are

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$Y = \overline{AB}$

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(C) The circuit consists of two diodes $D_1$ and $D_2$ connected to inputs $A$ and $B$,followed by an $npn$ transistor.If both inputs $A$ and $B$ are at low potential $(0)$,the diodes are forward biased,and the potential at point $X$ is low. The transistor remains in the cut-off state,so the output $Y$ is at high potential $(1)$.If either $A$ or $B$ is at high potential $(1)$,the corresponding diode is reverse biased,but the other diode or the resistor path keeps the potential at $X$ low enough such that the transistor remains off,resulting in $Y = 1$.If both $A$ and $B$ are at high potential $(1)$,the potential at $X$ becomes high enough to turn the transistor $ON$. When the transistor is $ON$,the collector-emitter path acts as a short circuit to ground,pulling the output $Y$ to low potential $(0)$.This behavior corresponds to the $NAND$ gate logic,where $Y = \overline{AB}$.

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$

In the following circuit,the correct relation between output $(Y)$ and inputs $A$ and $B$ will be

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