In the following $APs,$ find the missing terms in the boxes: $\square, 38, \square, \square, \square, -22$

(A) Let the $A.P.$ be $a_1, a_2, a_3, a_4, a_5, a_6.$
Given: $a_2 = 38$ and $a_6 = -22.$
We know the general term formula: $a_n = a + (n-1)d.$
For $n=2$: $a + d = 38$ $...(1)$
For $n=6$: $a + 5d = -22$ $...(2)$
Subtracting equation $(1)$ from $(2)$:
$(a + 5d) - (a + d) = -22 - 38$
$4d = -60$
$d = -15$
Substituting $d = -15$ in equation $(1)$:
$a + (-15) = 38$
$a = 38 + 15 = 53$
Now,finding the missing terms:
$a_1 = a = 53$
$a_3 = a + 2d = 53 + 2(-15) = 53 - 30 = 23$
$a_4 = a + 3d = 53 + 3(-15) = 53 - 45 = 8$
$a_5 = a + 4d = 53 + 4(-15) = 53 - 60 = -7$
Thus,the missing terms are $53, 23, 8,$ and $-7$.