In the first alloy,zinc and copper are in the | vedclass

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(A) Let the fraction of zinc in the first alloy be $\frac{1}{1+2} = \frac{1}{3}.$Let the fraction of zinc in the second alloy be $\frac{2}{2+3} = \fra

Vedclass · Accepted Answer

$3:10$

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(A) Let the fraction of zinc in the first alloy be $\frac{1}{1+2} = \frac{1}{3}.$Let the fraction of zinc in the second alloy be $\frac{2}{2+3} = \frac{2}{5}.$Let the fraction of zinc in the final alloy be $\frac{5}{5+8} = \frac{5}{13}.$Using the rule of alligation:Ratio of alloys = $\left| \frac{2}{5} - \frac{5}{13} ight| : \left| \frac{5}{13} - \frac{1}{3} ight|$$= \left| \frac{26-25}{65} ight| : \left| \frac{15-13}{39} ight|$$= \frac{1}{65} : \frac{2}{39}$$= \frac{1}{5 	imes 13} : \frac{2}{3 	imes 13}$$= \frac{1}{5} : \frac{2}{3} = 3 : 10.$

In the first alloy,zinc and copper are in the ratio $1:2.$ In the second alloy,the same elements are in the ratio $2:3.$ If these two alloys are mixed to form a new alloy in which the two elements are in the ratio $5:8,$ the ratio of these two alloys in the new alloy is

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