In the figure shown,three AC voltmeters are c | vedclass

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(A) In an $LCR$ series circuit,the voltage across the inductor is $V_L = I X_L = I(\omega L)$ and the voltage across the capacitor is $V_C = I X_C = I

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$V_2 = 0$

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(A) In an $LCR$ series circuit,the voltage across the inductor is $V_L = I X_L = I(\omega L)$ and the voltage across the capacitor is $V_C = I X_C = I(\frac{1}{\omega C})$.The voltmeter $V_2$ is connected across the series combination of the inductor and the capacitor.The reading of voltmeter $V_2$ is given by $V_2 = |V_L - V_C| = |I X_L - I X_C| = I |X_L - X_C|$.At resonance,the inductive reactance equals the capacitive reactance,i.e.,$X_L = X_C$ or $\omega L = \frac{1}{\omega C}$.Substituting this into the expression for $V_2$,we get $V_2 = I |X_L - X_L| = 0$.Therefore,at resonance,the reading of voltmeter $V_2$ is $0$.

In the figure shown,three $AC$ voltmeters are connected. The circuit is at resonance.

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