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(A) According to the equation of continuity,the total flow rate $Q_{total}$ is equal to the sum of the flow rates in the two branches.$Q_{total} = A_1

Vedclass · Accepted Answer

$5$

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(A) According to the equation of continuity,the total flow rate $Q_{total}$ is equal to the sum of the flow rates in the two branches.$Q_{total} = A_1 v_p + A_2 v_Q$Given:$Q_{total} = 0.1\, m^3/sec$$A_1 = A/3 = 10^{-2}/3\, m^2$$A_2 = 2A/3 = 2 	imes 10^{-2}/3\, m^2$$v_p = 20\, m/sec$Substituting the values:$0.1 = (A/3) 	imes 20 + (2A/3) 	imes v_Q$Multiply by $3/A$:$0.1 	imes (3/A) = 20 + 2 v_Q$$0.3 / 10^{-2} = 20 + 2 v_Q$$30 = 20 + 2 v_Q$$10 = 2 v_Q$$v_Q = 5\, m/sec$

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