In the figure given below, A, B. and C are th | vedclass

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Question

$(i)$ The current in the ammeters $B$ and $C$ is inversely proportional to the value of resistance in the parallel branch. Therefore,

$\frac{	ext

Vedclass · Accepted Answer

Vedclass · Answer

$(i)$ The current in the ammeters $B$ and $C$ is inversely proportional to the value of resistance in the parallel branch. Therefore,

$\frac{	ext { reading of ammeter } C}{	ext { reading of ammeter } B}=\frac{6}{3}=2$

Therefore, reading of ammeter $C$

$=2 	imes 0.5=1.0 A$

Hence, reading of ammeter $A$

$=(0.5+1.0) A =1.5 A$

Let the total resistance of the circuit be $R$.

Therefore, $\quad R =2+ R _{ p },$ where

$\frac{1}{ R _{ P }}=\frac{1}{3}+\frac{1}{6}=\frac{1}{2}$ or $R _{ P }=2\,ohm.$

Therefore, $\quad R =2+2=4 ohm .$

In the figure given below, $A, B$. and $C$ are three ammeters. The ammeter $B$ reads $0.5\, A .$ (All the ammeters have negligible resistance.) Calculate
$(i)$ the readings in the ammeters $A$ and $C$. $(ii)$ the total resistance of the circuit.

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In the figure given below, $A, B$. and $C$ are three ammeters. The ammeter $B$ reads $0.5\, A .$ (All the ammeters have negligible resistance.) Calculate $(i)$ the readings in the ammeters $A$ and $C$. $(ii)$ the total resistance of the circuit.