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(D) The prism is a triangle with base angles $60^{\circ}$ and $30^{\circ}$.The third angle $A$ of the prism is given by:$A = 180^{\circ} - (60^{\circ}

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(D) The prism is a triangle with base angles $60^{\circ}$ and $30^{\circ}$.The third angle $A$ of the prism is given by:$A = 180^{\circ} - (60^{\circ} + 30^{\circ}) = 180^{\circ} - 90^{\circ} = 90^{\circ}$.For a prism,the relation between the angle of incidence $i$,angle of emergence $e$,prism angle $A$,and angle of deviation $\delta$ is:$i + e = A + \delta$.From the diagram,the angle of incidence $i = 45^{\circ}$ and the angle of emergence $e = 60^{\circ}$.Substituting these values into the formula:$45^{\circ} + 60^{\circ} = 90^{\circ} + \delta$$105^{\circ} = 90^{\circ} + \delta$$\delta = 105^{\circ} - 90^{\circ} = 15^{\circ}$.Thus,the angular deviation is $15^{\circ}$.

In the diagram,a ray is passing through a broken prism. Find the angular deviation for the ray. (in $^{\circ}$)

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