In the density measurement of a cube, the mas | vedclass

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Question

$\begin{array}{l} ho  = \frac{m}{v}\ Maximum\,\% \,error\,in\,ho \,will\,be\,given\,by\ \frac{{\Delta p}}{p} 	imes 100\%  = \left( {\

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$\begin{array}{l} ho  = \frac{m}{v}\ Maximum\,\% \,error\,in\,ho \,will\,be\,given\,by\ \frac{{\Delta p}}{p} 	imes 100\%  = \left( {\frac{{\Delta m}}{m}} ight) 	imes 100\%  + 3\left( {\frac{{\Delta L}}{L}} ight) 	imes 100\% \,\,...\left( i ight)\ This\,is\,not\,applicable\,as\,error\,is\,big. \end{array}$

$\begin{array}{l} {ho _{\min }} = \frac{{{m_{\min }}}}{{{v_{\max }}}} = \frac{{9.9}}{{{{\left( {0.11} ight)}^3}}} = 7438kg/{m^3}\ and \,{ho _{\max \,}} = \frac{{{m_{\max }}}}{{{v_{\min }}}} = \frac{{10.1}}{{{{\left( {0.09} ight)}^3}}} = 13854.6kg/{m^3}\ \Delta ho  = 6416.6\,\,kg/{m^3}\ \end{array}$

In the density measurement of a cube, the mass and edge length are measured as $(10.00 \pm 0.10)\,\,kg\,$ and $(0.10 \pm 0.01)\,\,m\,$ respectively. The error in the measurement of density is

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