In the combination of the following gates,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given circuit consists of two $AND$ gates,two $NOT$ gates,and one $OR$ gate.$1$. The upper $AND$ gate receives inputs $A$ and $\overline{B}$ (

Vedclass · Accepted Answer

$A\cdot \overline {B} + \overline {A} \cdot B$

Vedclass · Answer

(B) The given circuit consists of two $AND$ gates,two $NOT$ gates,and one $OR$ gate.$1$. The upper $AND$ gate receives inputs $A$ and $\overline{B}$ (since $B$ passes through a $NOT$ gate). Its output is $A \cdot \overline{B}$.$2$. The lower $AND$ gate receives inputs $\overline{A}$ (since $A$ passes through a $NOT$ gate) and $B$. Its output is $\overline{A} \cdot B$.$3$. These two outputs are fed into an $OR$ gate. Therefore,the final output $Y$ is the sum of these two expressions: $Y = A \cdot \overline{B} + \overline{A} \cdot B$.This is the Boolean expression for an $XOR$ (Exclusive-$OR$) gate.

In the combination of the following gates,the output $Y$ can be written in terms of inputs $A$ and $B$ as

Similar Questions

An $AND$ gate is followed by a $NOT$ gate in series. With two inputs '$A$' and '$B$',the Boolean expression for the output '$Y$' will be

The truth table of the given circuit diagram is:

The combination of the gates shown will produce:

Which of the following is the symbol for a $NAND$ gate?

In the digital circuit,the inputs are as shown in the figure. The Boolean expression for output $Y$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module