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(D) In the given circuit,the two diodes $D_{1}$ and $D_{2}$ are connected in series with a $DC$ voltage source. For the circuit to conduct,both diodes

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(D) In the given circuit,the two diodes $D_{1}$ and $D_{2}$ are connected in series with a $DC$ voltage source. For the circuit to conduct,both diodes must be forward-biased. However,looking at the orientation of the diodes,$D_{1}$ is forward-biased while $D_{2}$ is reverse-biased. In a series circuit,the current $I$ is the same through all components. Since $D_{2}$ is reverse-biased,it offers a very high resistance,effectively acting as an open switch. Consequently,the entire potential difference of the battery appears across the reverse-biased diode $D_{2}$,while the potential difference across the forward-biased diode $D_{1}$ is negligible (approximately $0.7 \ V$ for Silicon). If the potential differences across $D_{1}$ and $D_{2}$ are stated to be equal,it implies that the circuit configuration or the assumption of identical characteristics must be re-evaluated,or the diodes are operating in a specific breakdown region. Given the standard interpretation,the potential difference across a reverse-biased diode is much larger than that across a forward-biased one.

In the circuit shown in the figure,the non-zero potential difference across diode $D_{1}$ and that across diode $D_{2}$ are equal. Are the diodes identical in characteristics? Explain.

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