In the circuit shown below, the power develop | vedclass

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(b) $P = \frac{{{V^2}}}{R}$$ \Rightarrow $ $\frac{{{P_1}}}{{{P_2}}} = \frac{{{R_2}}}{{{R_1}}}$$ \Rightarrow $ $\frac{6}{{{P_2}}} = \frac{4}{6} = \frac

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(b) $P = \frac{{{V^2}}}{R}$$ \Rightarrow $ $\frac{{{P_1}}}{{{P_2}}} = \frac{{{R_2}}}{{{R_1}}}$$ \Rightarrow $ $\frac{6}{{{P_2}}} = \frac{4}{6} = \frac{2}{3}$$ \Rightarrow $ ${P_2} = 9\,W$

In the circuit shown below, the power developed in the $6$ $\Omega$ resistor is $6\, watt$. The power in watts developed in the $4$ $ \Omega$ resistor is

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