In the circuit shown,when the key K is presse | vedclass

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(D) At $t = 0$,the capacitor acts as a short circuit (it is uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I$ th

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At $t = 0$,$I = 2\,mA$ and with time it decreases to $1\,mA$

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(D) At $t = 0$,the capacitor acts as a short circuit (it is uncharged). The total resistance in the circuit is $1000\,\Omega$. Thus,the current $I$ through the resistor $AB$ is $I = \frac{2\,V}{1000\,\Omega} = 2\,mA$.As time passes,the capacitor charges. As it charges,its potential difference increases,which opposes the flow of current. After a long time $(t 	o \infty)$,the capacitor is fully charged and acts as an open circuit. The current then flows through both resistors in series. The total resistance becomes $1000\,\Omega + 1000\,\Omega = 2000\,\Omega$. The current $I$ through the resistor $AB$ becomes $I = \frac{2\,V}{2000\,\Omega} = 1\,mA$.Therefore,at $t = 0$,$I = 2\,mA$,and as $t$ increases,$I$ decreases to $1\,mA$.

In the circuit shown,when the key $K$ is pressed at time $t = 0$,which of the following statements about current $I$ in the resistor $AB$ is true?

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