In the circuit shown, the power developed in | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$P_{6}=I_{6}^{2} 	imes R \Rightarrow 6=I_{6}^{2} 	imes 6 \Rightarrow I_{6}=1$

$\mathrm{I}_{4} 	imes 4=1 	imes 6 \Rightarrow \mathrm{I}_{4}=1.5$

Vedclass · Accepted Answer

$9$

Vedclass · Answer

$P_{6}=I_{6}^{2} 	imes R \Rightarrow 6=I_{6}^{2} 	imes 6 \Rightarrow I_{6}=1$

$\mathrm{I}_{4} 	imes 4=1 	imes 6 \Rightarrow \mathrm{I}_{4}=1.5$

$P_{4}=(1.5)^{2} 	imes 4=2.25 	imes 4=9 \mathrm{\,W}$

In the circuit shown, the power developed in the $6\,\Omega $ resistor is $6\,W.$ The power developed in the $4\,\Omega $ resistor is .............. $W$

Similar Questions

An expression for rate of heat generated, if a current of $I$ ampere flows through a resistance of $R$ $\Omega$, is

The internal resistance of a primary cell is $4\, ohm$. It generates a current of $0.2\, amp$ in an external resistance of $21\, ohm$. The rate at which chemical energy is consumed in providing the current is .............. $J/s$

Three electric bulbs of $200\,W,\,\,200\,W$ and $400\,W$ are shown in figure. The resultant power of the combination is ................ $W$

If two wires having resistance $R$ and $2R$. Both joined in series and in parallel then ratio of heat generated in this situation, applying the same voltage,

Resistances are arranged in a cyclic order to form a balanced wheatstone bridge as shown in figure. Ratio of power consumed in the branches $P + Q$ and $R + S$ is