In the circuit shown,the current in the $1\,\Omega$ resistor is

Kirchhoff's first law $(\Sigma i = 0)$ and second law $(\Sigma iR = \Sigma E)$ are based on which of the following respectively? (Where the symbols have their usual meanings.)

Three resistances $P, Q, R$ each of $2 \,\Omega$ and an unknown resistance $S$ form the four arms of a Wheatstone bridge circuit. When a resistance of $6 \,\Omega$ is connected in parallel to $S$,the bridge gets balanced. What is the value of $S$ in $\Omega$?

In the given figure: $V_1=V, V_2=\alpha V, R_1=\beta R, R_2=\gamma R$,where $\alpha, \beta$,and $\gamma$ are positive real numbers. The value of current $I$ is

The resistance of each arm of the Wheatstone bridge is $10 \, \Omega$. A resistance of $10 \, \Omega$ is connected in series with a galvanometer. Then, the equivalent resistance across the battery will be:

The current through the $1 \Omega$ resistance in the following circuit is (in $A$)