In the circuit given, $E = 6.0 \, V$, $R_1 = 100 \, \Omega$, $R_2 = R_3 = 50 \, \Omega$, and $R_4 = 75 \, \Omega$. The equivalent resistance of the circuit, in $\Omega$, is:

In the circuit element given here,if the potential at point $B$,$V_B = 0$,then the potentials of $A$ and $D$ are given as

$A$ wire when connected to $220\,V$ mains supply has power dissipation $P_1$. Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is $P_2$. Then $P_2:P_1$ is

What is the current $I$ (in $A$) flowing through the given circuit?

In the circuit shown,the cells $A$ and $B$ have negligible resistance. For $V_{A} = 12 \; V$,$R_{1} = 500 \; \Omega$ and $R = 100 \; \Omega$,the galvanometer $(G)$ shows no deflection. The value of $V_{B}$ is .... $V$.

Two wires of the same material having lengths and radii in the ratio of $3:4$ and $3:2$ respectively are connected in parallel with a potential source of $6 \ V$. The ratio of currents flowing through them $I_1:I_2$ is . . . . . . .