In the circuit given,the correct relation for | vedclass

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(C) Wheatstone bridge is said to be balanced when no current flows through the galvanometer $(G)$.In the given circuit,the resistors $P$ and $S$ are i

Vedclass · Accepted Answer

$\frac{P}{R} = \frac{S}{Q}$

Vedclass · Answer

(C) Wheatstone bridge is said to be balanced when no current flows through the galvanometer $(G)$.In the given circuit,the resistors $P$ and $S$ are in one arm,and $R$ and $Q$ are in the other arm.For a balanced bridge,the ratio of resistances in the opposite arms must be equal.Specifically,the potential at the two terminals of the galvanometer must be equal.Applying the condition for a balanced Wheatstone bridge,the ratio of the resistances in the adjacent arms must satisfy $\frac{P}{S} = \frac{R}{Q}$,which can be rearranged as $\frac{P}{R} = \frac{S}{Q}$.Therefore,option $C$ is the correct relation.

In the circuit given,the correct relation for a balanced Wheatstone bridge is

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