In the circuit diagrams (A, B, C and D) shown | vedclass

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(D) In the half-deflection method,a high resistance $R$ is connected in series with the galvanometer to maintain a nearly constant current,and a shunt

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Circuit $D$ with $G = \frac{RS}{R - S}$

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(D) In the half-deflection method,a high resistance $R$ is connected in series with the galvanometer to maintain a nearly constant current,and a shunt resistance $S$ is connected in parallel with the galvanometer to reduce the deflection to half.The circuit diagram $D$ shows a high resistance $R$ in series with the galvanometer $G$,and a shunt resistance $S$ connected in parallel with the galvanometer through a key $K_2$.When key $K_1$ is closed and $K_2$ is open,the current $I$ flows through $R$ and $G$. When $K_2$ is closed,the shunt $S$ is introduced,and the current through the galvanometer becomes $I/2$. The galvanometer resistance $G$ is then given by the formula $G = \frac{RS}{R - S}$.

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