In the circuit diagram shown in the figure,the current through the zener diode is (in $mA$)

$A$ Zener diode having a breakdown voltage equal to $5 \, V$ is used in the voltage regulator circuit shown in the figure. The current through the diode is ........ $mA$.

In a Zener regulated power supply, a Zener diode with $V_z = 6 \, V$ is used for regulation. The load current is $4 \, mA$ and the unregulated input voltage is $10 \, V$. To get a Zener current five times the load current, the value of the series resistor $R_S$ is nearly:

The figure represents a voltage regulator circuit using a Zener diode. The breakdown voltage of the Zener diode is $6\,V$ and the load resistance is $R_L = 4\,k\Omega.$ The series resistance of the circuit is $R_i = 1\,k\Omega.$ If the battery voltage $V_B$ varies from $8\,V$ to $16\,V,$ what are the minimum and maximum values of the current through the Zener diode?

In the given circuit,the value of $I_{L}$ (in $mA$) will be: (in $.5$)

In the diagram shown,the Zener diode has a reverse breakdown voltage of $V_Z$. The current through the load resistance $R_L$ is $I_L$. The current through the Zener diode is