In the chemical reaction $Cl_2 + H_2S \to 2HCl + S$,the oxidation number of sulphur changes from
- A$0$ to $2$
- B$2$ to $0$
- C$-2$ to $0$
- D$-2$ to $-1$
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Similar Questions
Match the following:
Compound Oxidation number $1$. $CrO_5$ $a$. $+6$ $2$. $H_2SO_4$ $b$. $+1$ $3$. $C_4OCl_2$ $c$. $-1$ $4$. $(CH_3)_2SO$ $d$. $+2$
| Compound | Oxidation number |
| $1$. $CrO_5$ | $a$. $+6$ |
| $2$. $H_2SO_4$ | $b$. $+1$ |
| $3$. $C_4OCl_2$ | $c$. $-1$ |
| $4$. $(CH_3)_2SO$ | $d$. $+2$ |
Medium
View SolutionSelect the compound in which chlorine is assigned the oxidation number $+5$.
Easy
View SolutionThe oxidation number of phosphorus in $Ba(H_2PO_2)_2$ is $:-$
Medium
View Solution$KMnO_4$ acts as an oxidising agent in the neutral medium and gets reduced to $MnO_2$. What is the equivalent weight of $KMnO_4$ in a neutral medium?
Easy
View SolutionEquivalent weight of $KMnO_4$ acting as an oxidant in acidic medium is equal to
Medium
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