In the case of a bar magnet,lines of magnetic induction:

$A$ cylindrical magnetic rod has length $5 \ cm$ and diameter $1 \ cm$. It has uniform magnetization $M = 5.3 \times 10^{3} \ A/m$. Its net magnetic dipole moment is nearly (take $\pi = 22/7$):

$A$ cylindrical magnetic rod has length $5 \ cm$ and diameter $1 \ cm$. It has uniform magnetization $5.3 \times 10^3 \ A/m$. Its net magnetic dipole moment is nearly

$A$ magnetized wire of magnetic moment $M$ and length $L$ is bent into an arc of a circle subtending an angle of $60^{\circ}$ at the center. The new magnetic moment is:

The intensity of magnetization of a bar magnet is $5.0 \times 10^{4} \text{ A m}^{-1}$. The magnetic length and the area of cross-section of the magnet are $12 \text{ cm}$ and $1 \text{ cm}^{2}$ respectively. The magnitude of the magnetic moment of this bar magnet is (in $SI$ unit):

$A$ straight magnetic strip has a magnetic moment of $44 \text{ Am}^2$. If the strip is bent in a semicircular shape,its magnetic moment will be . . . . . . . $\text{Am}^2$ (Given $\pi = \frac{22}{7}$)