In the DNA of E. coli,the mole ratio of adeni | vedclass

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(B) According to Chargaff's rule,the amount of adenine $(A)$ is equal to thymine $(T)$ and the amount of cytosine $(C)$ is equal to guanine $(G)$.Give

Vedclass · Accepted Answer

$500000$

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(B) According to Chargaff's rule,the amount of adenine $(A)$ is equal to thymine $(T)$ and the amount of cytosine $(C)$ is equal to guanine $(G)$.Given,the molar ratio of adenine to cytosine is $\frac{A}{C} = 0.7$.Given,the number of moles of adenine $(A)$ = $350000$.Substituting the value of $A$ in the ratio:$0.7 = \frac{350000}{C}$$C = \frac{350000}{0.7} = 500000$.Since the number of moles of cytosine $(C)$ is equal to the number of moles of guanine $(G)$ in $DNA$,the number of moles of guanine is $500000$.

In the $DNA$ of $E. coli$,the mole ratio of adenine to cytosine is $0.7$. If the number of moles of adenine in the $DNA$ is $350000$,the number of moles of guanine is equal to:

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