Difficult
In sulphur estimation,$0.471 \ g$ of an organic compound gave $1.4439 \ g$ of barium sulphate. The percentage of sulphur in the compound is $.............$ (Nearest Integer) (Given: Atomic mass $Ba: 137 \ u, S: 32 \ u, O: 16 \ u$)
- A$41$
- B$42$
- C$40$
- D$38$
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Similar Questions
In an estimation of bromine by Carius method,$1.6 \ g$ of an organic compound gave $1.88 \ g$ of $AgBr$. The mass percentage of bromine in the compound is..........
(Atomic mass,$Ag = 108, Br = 80 \ g \ mol^{-1}$)
(Atomic mass,$Ag = 108, Br = 80 \ g \ mol^{-1}$)
DifficultJEE MAIN 2020
View Solution$0.400 \ g$ of an organic compound $(X)$ gave $0.376 \ g$ of $AgBr$ in Carius method for estimation of bromine. The $\%$ of bromine in the compound $(X)$ is $.........$. (Given: Molar mass $AgBr = 188 \ g \ mol^{-1}$,$Br = 80 \ g \ mol^{-1}$)
$6.46 \ g$ of $BaSO_4$ is obtained from $4.81 \ g$ of a compound in the estimation of sulphur by the Carius method. Calculate the percentage of sulphur in the compound. (Atomic masses: $Ba = 137, S = 32, O = 16$)
Medium
View SolutionThe reaction of $Q$ with $PhSNa$ yields an organic compound (major product) that gives a positive Carius test on treatment with $Na_2O_2$ followed by the addition of $BaCl_2$. The correct option$(s)$ for $Q$ is (are):
Discuss the principle of estimation of halogens,sulphur and phosphorus present in an organic compound.
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