In solving the LP problem: "Minimize z = 6x + | vedclass

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(B) To identify the redundant constraints,we analyze the feasible region defined by the given constraints:$1$. $x \geq 6$$2$. $y \geq 2$$3$. $2x + y \

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$2x + y \geq 10, x \geq 0, y \geq 0$

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(B) To identify the redundant constraints,we analyze the feasible region defined by the given constraints:$1$. $x \geq 6$$2$. $y \geq 2$$3$. $2x + y \geq 10$$4$. $x \geq 0, y \geq 0$If $x \geq 6$ and $y \geq 2$,then $2x + y \geq 2(6) + 2 = 12 + 2 = 14$. Since $14 > 10$,the constraint $2x + y \geq 10$ is automatically satisfied whenever $x \geq 6$ and $y \geq 2$ are satisfied.Similarly,if $x \geq 6$ and $y \geq 2$,then $x \geq 0$ and $y \geq 0$ are automatically satisfied.Thus,the constraints $2x + y \geq 10, x \geq 0, y \geq 0$ are redundant because they do not restrict the feasible region further than $x \geq 6$ and $y \geq 2$ already do.

In solving the $LP$ problem: "Minimize $z = 6x + 10y$ subject to $x \geq 6, y \geq 2, 2x + y \geq 10, x \geq 0, y \geq 0$." The redundant constraints are $....$

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