In pyrrole,the electron density is maximum on

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(D) In pyrrole,the lone pair of electrons on the nitrogen atom is involved in the aromatic sextet. Due to the resonance effect,the electron density is

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$2$ and $5$

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(D) In pyrrole,the lone pair of electrons on the nitrogen atom is involved in the aromatic sextet. Due to the resonance effect,the electron density is delocalized over the ring. When an electrophile attacks,the intermediate carbocation (sigma complex) is more stable when the electrophile attacks at the $C_{2}$ or $C_{5}$ positions because the positive charge can be delocalized over more atoms,including the nitrogen atom. Therefore,the electron density is maximum at the $C_{2}$ and $C_{5}$ positions.

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