In the presence of AlCl_3,benzene and n-propy | vedclass

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Question

(D) In the Friedel-Crafts alkylation of benzene with $n$-propyl bromide in the presence of $AlCl_3$,the primary carbocation $(CH_3-CH_2-CH_2^+)$ forme

Vedclass · Accepted Answer

Isopropyl benzene

Vedclass · Answer

(D) In the Friedel-Crafts alkylation of benzene with $n$-propyl bromide in the presence of $AlCl_3$,the primary carbocation $(CH_3-CH_2-CH_2^+)$ formed initially undergoes a $1, 2$-hydride shift to form a more stable secondary carbocation $(CH_3-CH^+-CH_3)$.This secondary carbocation then attacks the benzene ring to form isopropyl benzene (cumene) as the major product.

In the presence of $AlCl_3$,benzene and $n$-propyl bromide react in a Friedel-Crafts alkylation reaction to form:

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