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(D) The photoelectric effect is an instantaneous process,so it will not be delayed. Since the frequency of the incident radiation remains the same,the

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The saturation current will decrease.

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(D) The photoelectric effect is an instantaneous process,so it will not be delayed. Since the frequency of the incident radiation remains the same,the maximum kinetic energy of the emitted photoelectrons remains unchanged. The saturation current is directly proportional to the intensity of the incident radiation. Therefore,if the intensity of the radiation is decreased,the number of photoelectrons emitted per unit time decreases,which leads to a decrease in the saturation current. Thus,the correct option is $D$.

In the photoelectric effect,if a radiation of weak intensity is used instead of a radiation of strong intensity,but of the same suitable frequency,then:

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