In nitroprusside ion, the iron exists as Fe^{ | vedclass

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Question

The nitroprusside ion is $\left[ Fe ( CN )_6 NO ^{+}\right]^{2-}$. The solid state magnetic moment measurement reveals the presence of $4$ unpaired el

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magnetic moment in solid state

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The nitroprusside ion is $\left[ Fe ( CN )_6 NO ^{+}\right]^{2-}$. The solid state magnetic moment measurement reveals the presence of $4$ unpaired electrons in $Fe$, which must be then in $Fe ^{2+}\left(3 d ^6\right)$, and not $Fe ^{3+}\left(3 d ^5\right)$

In nitroprusside ion, the iron exists as $Fe^{2+}$ and $NO$ as $NO^+$ rather than $Fe^{3+}$ and $NO$ respectively. These forms of ions are established with the help of

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