(A) The word $PERMUTATIONS$ contains $12$ letters in total,where the letter $T$ repeats $2$ times and all other letters are distinct.If the word must

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(A) The word $PERMUTATIONS$ contains $12$ letters in total,where the letter $T$ repeats $2$ times and all other letters are distinct.If the word must start with $P$ and end with $S$,we fix these two letters at the extreme ends.This leaves $12 - 2 = 10$ letters to be arranged in the middle positions.Among these $10$ letters,the letter $T$ still repeats $2$ times.The number of arrangements is given by the formula $\frac{10!}{2!} = \frac{3628800}{2} = 1814400$.

Class 11 Mathematics Permutation and Combination Definition of permutation, Number of permutations with or without repetition, Conditional permutations

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In how many ways can the letters of the word $PERMUTATIONS$ be arranged if the words start with $P$ and end with $S$?

A
$1814400$
B
$1814400$
C
$1814400$
D
$1814400$

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In how many ways can the letters of the word $PERMUTATIONS$ be arranged if the words start with $P$ and end with $S$?

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