In how many ways can 10 balls be divided betw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the two boys be $A$ and $B$.Case $1$: $A$ receives $2$ balls and $B$ receives $8$ balls.The number of ways is given by $\binom{10}{2} = \frac{

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(C) Let the two boys be $A$ and $B$.Case $1$: $A$ receives $2$ balls and $B$ receives $8$ balls.The number of ways is given by $\binom{10}{2} = \frac{10!}{2!8!} = \frac{10 	imes 9}{2 	imes 1} = 45$.Case $2$: $A$ receives $8$ balls and $B$ receives $2$ balls.The number of ways is given by $\binom{10}{8} = \frac{10!}{8!2!} = 45$.Since these are two distinct scenarios,the total number of ways is $45 + 45 = 90$.

In how many ways can $10$ balls be divided between two boys,such that one receives $2$ balls and the other receives $8$ balls?

Similar Questions

If ${}^{10}P_r = 604800$ and ${}^{10}C_r = 120$,then $r =$

The product of any $r$ consecutive natural numbers is always divisible by

In an examination of $9$ papers,a candidate is successful only if they pass in more papers than they fail. In how many ways can the candidate be unsuccessful?

The total number of ways of selecting $4$ letters from all the letters of the word $TSEAMCET$ is

$A$ bag contains $5$ black and $6$ red balls. Determine the number of ways in which $2$ black and $3$ red balls can be selected.

Vedclass Test Series

Exam Paper Generator

Online Exam Module