In how many ways can a team of 11 players be | vedclass

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(B) Total players available = $25$.Players to be included = $6$.Players to be excluded = $5$.Remaining players to choose from = $25 - 6 - 5 = 14$.Play

Vedclass · Accepted Answer

$2002$

Vedclass · Answer

(B) Total players available = $25$.Players to be included = $6$.Players to be excluded = $5$.Remaining players to choose from = $25 - 6 - 5 = 14$.Players already selected = $6$.Players still needed to complete the team of $11$ = $11 - 6 = 5$.Therefore,the number of ways to choose $5$ players from the remaining $14$ is given by the combination formula $^{n}C_{r} = \frac{n!}{r!(n-r)!}$.$^{14}C_{5} = \frac{14 	imes 13 	imes 12 	imes 11 	imes 10}{5 	imes 4 	imes 3 	imes 2 	imes 1} = 14 	imes 13 	imes 11 = 2002$.

In how many ways can a team of $11$ players be formed out of $25$ players,if $6$ out of them are always to be included and $5$ are always to be excluded?

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