In Heisenberg's uncertainty equation $\Delta x \times \Delta p \ge \frac{h}{4\pi}$,$\Delta p$ stands for:

Calculate the uncertainty in the position of a particle when the uncertainty in momentum is $1 \times 10^{-3} \, g \, cm \, sec^{-1}$.

Calculate the mass of an elementary particle,which is accelerated to twice the velocity of light with the precision $\pm 1 \%$,and has $1.05 \times 10^{-13} \ m$ uncertainty in position. $(h = 6.6 \times 10^{-34} \ kg \ m^2 \ s^{-1})$

For an electron,if the uncertainty in velocity is $\Delta \nu$,the uncertainty in its position $(\Delta x)$ is given by:

The uncertainty in the position of a particle of mass $0.25 \, kg$ is $10^{-5} \, m$. The uncertainty in its velocity is ...... $m/s$.

Write down Heisenberg's uncertainty principle.