In the given circuit,the voltage across the inductor will be ..... $V$.

In an $A.C.$ circuit,a resistance $R = 40 \ \Omega$ and an inductance $L$ are connected in series. If the phase angle between voltage and current is $45^{\circ}$,then the value of the inductive reactance is $(\tan 45^{\circ} = 1)$. (in $Omega$)

$A$ resistance of $300\,\Omega$ and an inductance of $\frac{1}{\pi}\,H$ are connected in series to an $AC$ voltage source of $20\,V$ and $200\,Hz$ frequency. The phase angle between the voltage and current is:

For the $L-R$ circuit shown in the figure,calculate the phase angle in degrees if the frequency is $f = 100/\pi \ Hz$. The inductance is $L = 0.025 \ H$ and the resistance is $R = 5 \ \Omega$.

$A$ $220\, V$,$50\, Hz$ $ac$ source is connected to an inductance of $0.2\, H$ and a resistance of $20\, \Omega$ in series. What is the current in the circuit (in $, A$)?

An $AC$ generator $10 \, V$ (rms) at $200 \, rad/s$ is connected in series with a $50 \, \Omega$ resistor, a $400 \, mH$ inductor, and a $200 \, \mu F$ capacitor. The rms voltage across the inductor is (in $V$)