In free space,an electromagnetic wave of $3 \; GHz$ frequency strikes an object of size $\frac{\lambda}{100}$,where $\lambda$ is the wavelength of the wave in free space. The phenomenon that occurs is .....

The frequency of radio waves corresponding to a wavelength of $10 \, m$ is

The ratio of the amplitude of the magnetic field to the amplitude of the electric field for an electromagnetic wave propagating in vacuum is equal to:

The efficiency of a bulb of power $60 \ W$ is $16 \%$. The peak value of the electric field produced by the electromagnetic radiation from the bulb at a distance of $2 \ m$ from the bulb is $\left(\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \ Nm^2 C^{-2}\right)$ (in $Vm^{-1}$)

Given below are two statements: one is labelled as Assertion $(A)$ and other is labelled as Reason $(R).$
Assertion $(A):$ Electromagnetic waves carry energy but not momentum.
Reason $(R):$ Mass of a photon is zero.
In the light of the above statements,choose the most appropriate answer from the options given below:

The velocity of an electromagnetic wave is parallel to: